okay, i'm stuck on a couple questions... :/

2!n! / 4!(n-5) = (n-1)! / (n-4)!

and..

(n+2)! / n! = 30

any help would be great, thanks! :)

Printable View

- Jan 18th 2010, 11:47 AMneeduhelpfactorial!
okay, i'm stuck on a couple questions... :/

2!n! / 4!(n-5) = (n-1)! / (n-4)!

and..

(n+2)! / n! = 30

any help would be great, thanks! :) - Jan 18th 2010, 11:54 AMVonNemo19
- Jan 18th 2010, 03:37 PMneeduhelp
could someone post the work involved with the first question, i'm lost lol

- Jan 18th 2010, 03:41 PMJhevon
- Jan 18th 2010, 04:23 PMneeduhelp
i have..

2!(n-1)(n-2)(n-3)(n-4) / 4! = (n-1)(n-2)(n-3) - Jan 18th 2010, 04:58 PMmr fantastic