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Math Help - Combination

  1. #1
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    Combination

    There are 20 footballer and 15 basketballer attending a sport conference . THe number of women footballer and that of women basketballer are 12 and 5 respectively . Four participants from this group are selected randomly to chair some sessions of panel discussion .

    (1) Find the probability that three footballer are selected .

    I don really understand the question , these 3 footballer are selected from the 20 footballer 15 basketballer OR 12 footballer 5 basketballer ?

    (2) Given that two women are selected , find the probability that both of them are footballer .
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  2. #2
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    Quote Originally Posted by thereddevils View Post
    There are 20 footballer and 15 basketballer attending a sport conference . THe number of women footballer and that of women basketballer are 12 and 5 respectively . Four participants from this group are selected randomly to chair some sessions of panel discussion .

    (1) Find the probability that three footballer are selected .

    I don really understand the question , these 3 footballer are selected from the 20 footballer 15 basketballer OR 12 footballer 5 basketballer ?

    (2) Given that two women are selected , find the probability that both of them are doctors .
    (1) \frac{{20 \choose 3} \cdot {15 \choose 1}}{{35 \choose 4}}. Your job is to understand where this answer has come from.

    (2) I don't see anything in the question about doctors so this part is currently impossible to answer.
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  3. #3
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    Quote Originally Posted by mr fantastic View Post
    (1) \frac{{20 \choose 3} \cdot {15 \choose 1}}{{35 \choose 4}}. Your job is to understand where this answer has come from.

    (2) I don't see anything in the question about doctors so this part is currently impossible to answer.
    Sorry , not doctor but footballers .
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  4. #4
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    Quote Originally Posted by thereddevils View Post
    Sorry , not doctor but footballers .
    \frac{{12 \choose 2} \cdot {23 \choose 2}}{{17 \choose 2} \cdot {18 \choose 2}}
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  5. #5
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    Quote Originally Posted by mr fantastic View Post
    \frac{{12 \choose 2} \cdot {23 \choose 2}}{{17 \choose 2} \cdot {18 \choose 2}}
    but the answer given is 0.4853
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