Thread: One bag contains 4 white balls

Question : One bag contains 4 white balls and 2 black balls; another contains 3 white balls and 5 black balls. If one ball is drawn from each bag, find the probability that (i) both are white , (ii) one is white and one is black.
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Pr(X = white ball from bag 1) = \frac{4}{6}

Pr(X = white ball from bag 2) = \frac{3}{8}

Hello, zorro!

One bag contains 4 white balls and 2 black balls.
Another contains 3 white balls and 5 black balls.
If one ball is drawn from each bag, find the probability that
. . (a) both are white
. . (b) one is white and one is black.

We have: .


(a) Both White.

. .

Therefore: .



(b) one W, one B

There are two scenariors:

. . [1] W from Bag 1, B from Bag 2: .

. . [2] B from Bag 1, W from Bag 2: .


Therefore: .

Originally Posted by zorro

Question : One bag contains 4 white balls and 2 black balls; another contains 3 white balls and 5 black balls. If one ball is drawn from each bag, find the probability that (i) both are white , (ii) one is white and one is black.
--------------------------------------------------------------------------------------------------------------------------

Pr(X = white ball from bag 1) = \frac{4}{6}

Pr(X = white ball from bag 2) = \frac{3}{8}

Draw a tree diagram.