Question : X is uniformly distributed over (0,10) calculate the probability that

i) X < 3

ii) X > 7

iii) 1 < X < 6

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Solution :

$\displaystyle P(x<3) = \frac{1}{3}$

$\displaystyle P(X>7) = \frac{1}{3}$

$\displaystyle P(1<X<6) = \frac{1}{5}$

Are these answer correct