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**nameck** box A contains 2 red balls,

box B contains 2 white balls,

box C contains 1 red ball and 1 white ball,

A box is selected at random (with equal probabilities) and one ball is taken at random from that box.

(i) Compute the probability of selecting a white ball using Bayes Rule.

A(1/3) _____ Red(1/6)

.........|____ Red(1/6)

B(1/3)______White(1/6)

........|_____White(1/6)

C(1/3)______Red(1/6)

........|_____White(1/6)

so.. P(White) = [(1/3)*(1/6)] + [(1/3)*(1/6)] + [(1/3)*(1/6)]

= 1/6

**Correct?**