I saw a exercise that I couldn't answer, but it seems so simple...
There is a chance that the book has a wrong answer (it says 5/6 is the answer), but I can't get that kind of an answer.
"There are 10 pieces, 4 of them are good. What the probability that you will pick alteast one good piece?"
So as far as I figured then here are combinations (10 3) = 10!/(3!*7!) = 120. So there are 120 ways to pick 3 pieces.
If the answer is right then there should be 100 outcomes out of 120 that you pick atleast 1 good piece (5/6), but how can you get such a number?