Thread: Probability

Hi again
This one is kind of tough. If anybody have a clue please let me know

Thanks

Originally Posted by mauro21pl

Hi again
This one is kind of tough. If anybody have a clue please let me know

Thanks

the proportion of people that have accidents in a fixed year is the sum
of the proportion in each category times the probability of accident in a year for that category:

In this case this is:

0.2*0.05+0.5*0.15+0.3*0.3 = 0.175

For the second part we can use Bayes' theorem:

P(good|no accidents) = P(no accidents|good)P(good)/P(no accidents)

..........................= (1-0.05)*0.2/(1-0.175) = 0.230

RonL