Is there a difference (either way) in the average miles traveled for each of two taxi companies during a randomly selected week? Assume that the populations are normally distributed.

α = 0.05

x-bar1 = 817

σ1 = 30

n1 = 35

x-bar2 = 743

σ2 = 40

n2 = 40

H0: µ1 = µ2

H1: µ1 does not equal µ2

For difference of means where σ1 and σ2 are known.

z= (817-743)/√((30^2/35)+(40^2/40)) = 9.13

How do I get the P value for this. 9.13 is not on the chart. It doesn’t even look right…