I have the following probability assesment table
no.of blemishes-0,1,2,3,4,5
probability-0.34,0.25,0.19,0.11,0.07,0.04

I was trying to select an event A i.e more than 2 blemishes and event B which is 4 or fewer blemishes.

means P(A>=2) and P(B<=4) inorder to calculate P(A) & P(B)how should I approach?Do I need proceed thru binomial distribution?

2. The probability of more than 2 blemishes is just 0.11+0.07+0.04 and probability of 4 or fewer blemishes is 1 - 0.04 = 0.96.

3. Thank you for the response. so then A intersection B should be 0.11+0.07 right?

4. Originally Posted by sgk1980
Thank you for the response. so then A intersection B should be 0.11+0.07 right?
Yes, since this is the event of 3 or 4 blemishes, just add those probabilities together

5. Thanks a lot.One more query if event A has atleast 1 blemish and event B has atmost 3 blemishes then AUB = 0.55(0.25 + 0.11+0.19) right?

6. Originally Posted by sgk1980
I have the following probability assesment table
no.of blemishes-0,1,2,3,4,5
probability-0.34,0.25,0.19,0.11,0.07,0.04

I was trying to select an event A i.e more than 2 blemishes and event B which is 4 or fewer blemishes.

means P(A>=2) and P(B<=4) inorder to calculate P(A) & P(B)how should I approach?Do I need proceed thru binomial distribution?
No indeed.
Just add up the corresponding probabilites from the given table.

7. Thank you .then A complement should be .30 right?