The probability of more than 2 blemishes is just 0.11+0.07+0.04 and probability of 4 or fewer blemishes is 1 - 0.04 = 0.96.
I have the following probability assesment table
I was trying to select an event A i.e more than 2 blemishes and event B which is 4 or fewer blemishes.
means P(A>=2) and P(B<=4) inorder to calculate P(A) & P(B)how should I approach?Do I need proceed thru binomial distribution?
Thanks In advance