Thread: Question on Poisson

The number of serious faults on a randomly chosen 1km stretch of motorway has a Poisson distribution of mean 2.1. The random variable X km is the distance between successive serious faults on the motorway.

Explain, using a Poisson distribution, why for $\displaystyle x\geq0$

$\displaystyle P(X>x)=e^{-2.1x}$

Originally Posted by I-Think

The number of serious faults on a randomly chosen 1km stretch of motorway has a Poisson distribution of mean 2.1. The random variable X km is the distance between successive serious faults on the motorway.


Explain, using a Poisson distribution, why for $\displaystyle x\geq0$

$\displaystyle P(X>x)=e^{-2.1x}$

Read this: http://imperator.usc.edu/~bruck/clas...xponential.pdf