Given the joint density function
f (x,y) = 6-x-y/ 8 , 0<x<2, 2<y<4
find P (1<Y<3|X=1).
i have got g(x)=(3-x)/4 and also f(y|x) = (6-x-y) / (2(3-x))
i substitute x=1 into (6-x-y) / (2(3-x)) and i got (5-y)
so i integrate (5-y) to dy from 1 to 3.
but it is not right.
did i miss something ?