math contest problem on probability.

Two fair coins are to be tossed once. For each head that results, one fair die is to be rolled. What is the probability that the sum of the die rolls is odd? ( Note that if no die is rolled the sum is 0)

I could think of the cases

HH the sum to be odd is 18/36
HT one die rolled 3/6 is odd
TH one die rolled 3/6 is odd
TT

I'm stuck from here....

Vicky.

My knowledge of probability is very basic so could this please be explained as easy as possible?

Quote:

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Originally Posted by Vicky1997

Two fair coins are to be tossed once. For each head that results, one fair die is to be rolled. What is the probability that the sum of the die rolls is odd? ( Note that if no die is rolled the sum is 0)

I could think of the cases

HH the sum to be odd is 18/36
HT one die rolled 3/6 is odd
TH one die rolled 3/6 is odd
TT

I'm stuck from here....

Vicky.

My knowledge of probability is very basic so could this please be explained as easy as possible?

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Pr(HH) = 1/4, Pr(HT) = 1/4 .....

So the answer will be (1/4)(18/36) + (1/4)(3/6) + .... = ....

Quote:

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Originally Posted by mr fantastic

Pr(HH) = 1/4, Pr(HT) = 1/4 .....

So the answer will be (1/4)(18/36) + (1/4)(3/6) + .... = ....

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Then it would be 1/8 + 1/8 + 1/8 = 3/8

Thank you!!