Originally Posted by

**rowdy3** One summer night at Bellair Lanes, a group of math professors went bowling. In true form, they decided to calculate their mean bowling score and standard deviation to use for the statistics problems. Here are the results: u(mean) 88, o(standard dev.)15.

Find the probability that if a math professor is selected, his or her score will be greater than 100.

100-88 / 15 = .8 normal cdf(.8,4) =.2118

Find the probability that, if a math professor is selected, his or her score will be between 50 and 100.

50-88 / 15 = -2.53 100-88 / 15 =.8 normal cdf(-2.53,.8)= .7824.

Did I do the problems right? Thanks