The question I need help understanding is below:

A balanced six-sided die is tossed twice. Let X be the highest number rolled.

a) Give the probability distribution for X.

The number of trials is two.

I need to figure out the probability that a certain number is the highest number displayed uppermost after a die is tossed, given that the die is tossed twice. So... If a six appears, what is the probability that it is the highest number of the two tossed? If I roll a six on one of the two tosses then it would seem more likely that it is the higher of the two numbers displayed. Is this thinking correct? How might I derive a binomial distribution from this problem?