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Math Help - Vectors and simple probability

  1. #1
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    Vectors and simple probability

    can anyone tell me the basics of vectors and simple probability and solve this Q for me ?

    In a group of 11 boys , 7 supports United and 4 supports City .
    (i) a boy is chosen at random from the group . state , as a fraction , the probability that he supports United .
    (ii) on another occasion two of the eleven boys are chosen at random . calculate the probability that they both supports City , giving your answer as a fraction
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  2. #2
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    Hello raza9990
    Quote Originally Posted by raza9990 View Post
    can anyone tell me the basics of vectors and simple probability and solve this Q for me ?

    In a group of 11 boys , 7 supports United and 4 supports City .
    (i) a boy is chosen at random from the group . state , as a fraction , the probability that he supports United .
    (ii) on another occasion two of the eleven boys are chosen at random . calculate the probability that they both supports City , giving your answer as a fraction
    Here's some basic stuff on probability. And here's something about vectors.

    (i) The probability is \frac{\text{number of successful outcomes}}{\text{number of possible outcomes}}=\frac{7}{11}

    (ii) In the same way, the probability that the first one supports City is \frac{4}{11}. If he does, there are then 10 boys left, 3 of whom support City. So the probability that the second supports City also is \frac{3}{10}.

    So the probability that they both support City is \frac{4}{11}\times\frac{3}{10}= \frac{6}{55}

    Grandad
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  3. #3
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    Quote Originally Posted by Grandad View Post
    Hello raza9990Here's some basic stuff on probability. And here's something about vectors.

    (i) The probability is \frac{\text{number of successful outcomes}}{\text{number of possible outcomes}}=\frac{7}{11}

    (ii) In the same way, the probability that the first one supports City is \frac{4}{11}. If he does, there are then 10 boys left, 3 of whom support City. So the probability that the second supports City also is \frac{3}{10}.

    So the probability that they both support City is \frac{4}{11}\times\frac{3}{10}= \frac{6}{55}

    Grandad
    thnk u
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