3 girls and 4 boys were standing in a circle. What is the probability that two girls are standing together, but the third one is not next to them?
GG***** the other girl can stand in 4 different places here
*GG**** other girl in 3 places
So in total: 2x(4+3+3) = 20
Is this correct? Do you have any other methods that you could show?
probability = no. ways you can arrange two girls together without third being adjacent / total no ways to arrange 3 girls and 4 boys in circle.
BGGB - C
First part is synomymous to arranging B,B,G,C on a straight line = 4!/2! = 12
Second part = 7!/3!4! = 35
Prob = 12/35