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Math Help - Any idea on it ?

  1. #1
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    Any idea on it ?

    Have any method to solve this question?
    Always in exam i feel tired to see this question
    Attached Thumbnails Attached Thumbnails Any idea on it ?-capture1.jpg  
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  2. #2
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    There's only three opponents. Simply list the possibilities.

    Pr(Beat all three) = (5/6)(3/4)(2/3)

    Pr(Win 2 matches) = Oh, you have to do SOME of the work.

    Pr(Lose 2 Matches) = (5/6)(1/4)(1/3)+(1/6)(3/4)(1/3)+(1/6)(1/4)(2/3)

    Pr(Lost to all three) = (1/6)(1/4)(1/3)

    Draw a tree.
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  3. #3
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    which means that
    when lose need to minus out such like
    6/6 - 5/6 = 1/6
    4/4 - 3/4 = 1/4
    3/3 - 2/3 = 1/3
    after that need to multiple up ?

    Between how about the one at least 2 win
    is it got (two wins multiple 1 lose) do until it finish ?
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  4. #4
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    I think you have it, but you WILL need to work on your english a little.

    Please show your work and we can see if you really have it.

    Good work. You are making a nice effort.
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  5. #5
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    oh ok!
    thanks for your advices
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