# Any idea on it ?

• Oct 31st 2009, 07:48 AM
warriow
Any idea on it ?
Have any method to solve this question?
Always in exam i feel tired to see this question (Crying)
• Oct 31st 2009, 07:55 AM
TKHunny
There's only three opponents. Simply list the possibilities.

Pr(Beat all three) = (5/6)(3/4)(2/3)

Pr(Win 2 matches) = Oh, you have to do SOME of the work.

Pr(Lose 2 Matches) = (5/6)(1/4)(1/3)+(1/6)(3/4)(1/3)+(1/6)(1/4)(2/3)

Pr(Lost to all three) = (1/6)(1/4)(1/3)

Draw a tree.
• Oct 31st 2009, 08:06 AM
warriow
which means that
when lose need to minus out such like
6/6 - 5/6 = 1/6
4/4 - 3/4 = 1/4
3/3 - 2/3 = 1/3
after that need to multiple up ?

Between how about the one at least 2 win
is it got (two wins multiple 1 lose) do until it finish ?
• Oct 31st 2009, 08:04 PM
TKHunny
I think you have it, but you WILL need to work on your english a little.

Please show your work and we can see if you really have it.

Good work. You are making a nice effort.
• Nov 1st 2009, 01:33 AM
warriow
oh ok!