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Thread: Probability

  1. February 4th 2007, 10:22 AM #1
    mauro21pl
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    Probability

    Poker diece is played simultaneously rolling 5 dice. Show that:
    P{two pair} = 0.2315
    thanks
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  2. February 4th 2007, 01:21 PM #2
    Plato
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    Calculate \left[{6 \choose 2} {(4)} \right]\frac{{\left( {5!} \right)}}{{\left( {2!} \right)^2 \left( {6!} \right)}}.
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« Proof | Help with Combinations »

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