Poker diece is played simultaneously rolling 5 dice. Show that:

P{two pair} = 0.2315

thanks

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- Feb 4th 2007, 10:22 AMmauro21plProbability
Poker diece is played simultaneously rolling 5 dice. Show that:

P{two pair} = 0.2315

thanks - Feb 4th 2007, 01:21 PMPlato
Calculate $\displaystyle \left[{6 \choose 2} {(4)} \right]\frac{{\left( {5!} \right)}}{{\left( {2!} \right)^2 \left( {6!} \right)}}.$