There is a bus with 6 people, and the bus will stop 10 times. All passengers are equally likely to get off anywhere. What is the prob. that no 2 people get off at the same stop?

I have C(6 10)= 10factorial/(6factorial*4factorial)=210 ways 6 people can get off at 10 stops.

But from there, I am stuck. I'm unsure of how to find whether 2 people will get off at the same stop. Any assistance is greatly appreciated.

Thanks.