# Thread: Probability pairings

1. ## Probability pairings

Hi All,

I am conpleting a question for college and was wodering if someone could hepl.
I have all questions done except this one.

A team consists of 6 Irish and 6 Scottish players. The teams are to be paired in groups for the purpose of determining room mates on a particular trip. If the parings are done at randon:
Find the probability that none of the Irish players has a Scottish room mate?

Any ideas?

2. Originally Posted by snewo
A team consists of 6 Irish and 6 Scottish players. The teams are to be paired in groups for the purpose of determining room mates on a particular trip. If the parings are done at randon:
Find the probability that none of the Irish players has a Scottish room mate
There are a total of $\frac{12!}{6!(2^6)}$ way to pair twelve players.

There are a total of $\frac{6!}{3!(2^3)}$ way to pair the six Scottish players with one another.

3. From where are you finding probability?

4. Originally Posted by snewo
From where are you finding probability?
I am not. That is your job.
I am simply helping you with the counting part.