non smoker light smoker heavy smoker total

men 369 33 45 474

women 341 34 41 416

total 737 67 86 890

2 people are randomly selected from 890 . Find probability that they will both be women??

Thanks,

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- Feb 3rd 2007, 01:39 PMair2slbone more probability
non smoker light smoker heavy smoker total

men 369 33 45 474

women 341 34 41 416

total 737 67 86 890

2 people are randomly selected from 890 . Find probability that they will both be women??

Thanks, - Feb 3rd 2007, 02:24 PMCaptainBlack
Probability that the first is a woman is 416/890

The probability that the second is a woman given that the first is a woman is

415/889 (that is the number of women left after one has been selected over

the total left)

So the required probability is the product of these, that is:

(416/890)*(415/889)~=0.2182.

RonL