if three unbias dices are thrown, what is probabilty that all three dices give the same no. i would attempt by 1/6 x 1/6 x 1/6 x 6 is it correct?
Hello, helloying!
Another approach . . .
If three unbiased dice are thrown,
what is probabilty that all three dice give the same number?
The first die can be any number (it doesn't matter).
The probability that the second die matches the first is: .$\displaystyle \tfrac{1}{6}$
The probability that the third die matches the first two is: .$\displaystyle \tfrac{1}{6}$
Therefore: .$\displaystyle P(\text{same number}) \;=\;\frac{1}{6} \times \frac{1}{6} \;=\;\frac{1}{36}$