Hello, bjanela!

I had to baby=talk my way through this one . . .

We are concerned with two outcomes in the first draw:You have 12 eggs, 2 of which are bad, and you choose 4 randomly.

Afterwards, 4 more are randomly chosen from the remaining 8.

Find the conditional probbability that the second batch of four were all good,

given that at least one of the first four was bad.

. . 1. One bad egg was drawn.

. . 2. Both bad eggs were drawn.

Case 1: One bad egg was drawn.

There are 12 eggs: 2 bad and 10 good

There are: . possible outcomes.

To get 1 B and 3 G, there are: . ways.

. .Hence: .

For the second draw, there are: 1B, 7G.

There are: . possible outcomes.

To get 4G, there are: . ways.

. . Hence: .

For Case 1: .

Case 2: Both bad eggs were drawn.

There are: . possible outcomes.

To get 2B and 2G, there are: . ways.

Hence: .

For the second draw, there are:

The probability of drawing 4G is: .

For Case 2: .

Therefore: .