Please help !
You have 2 fair coins and one two headed coin. You draw one coin randomly and flip and toss it twice. Given that both tosses resulted in heads, find the conditional probability that the two headed coin was chosen as a fraction--in lowest terms.
We also have to do this again, but assume thaqt we have 8 fair coins and one 2-headed coin.
Thanks!
Hello, bjanela!
We need Bayes' Theorem: .
We want: .You have 2 fair coins and one two-headed coin .
You draw one coin randomly and flip and toss it twice.
Given that both tosses resulted in heads, find the conditional probability
that the two-headed coin was chosen.
A fair coin is chosen: .
. . Then: .
. . Hence: .
is chosen: .
. . Then: .
. . Hence: .
So: .
Therefore: .
Do this again, with 8 fair coins and one 2-headed coin.
We want: .
A fair coin is chosen: .
. . Then: .
. . Hence: .
is chosen: .
. . Then: .
. . Hence: .
So: .
Therefore: .