For a sample of size n=100, proportion p=0.6, and at a 95% confidence level, the upper bound of the proportion is what?
0.096
0.696
0.050
0.025
P=0.6
n=100
c=95%, A=0.475 is z=196
se=sqr 0.6=.7745 sqr100=10 so .7745+10/95=.8797, this isn't set up right, please help me with this one. thanks for any help given.