For a sample of size n=100, proportion p=0.6, and at a 95% confidence level, the upper bound of the proportion is what?

0.096

0.696

0.050

0.025

P=0.6

n=100

c=95%, A=0.475 is z=196

se=sqr 0.6=.7745 sqr100=10 so .7745+10/95=.8797, this isn't set up right, please help me with this one. thanks for any help given.