Originally Posted by

**jut** In a communication system the probability, denoted Pr(), is

Pr(0 being transmitted) = 0.4

Pr(1 being transmitted) = 0.6

Pr(receive 0 | transmit 0) = 0.92

Pr(receive 1 | transmit 1) = 0.95

Notation: Given that a 0 was transmitted, prob of receiving a 0 is 0.92

**What's the prob of receiving 6 successive symbols without error?**

My first task, I suppose, is to find out the prob of receiving with no error. Would that prob equal

Pr(receive 0 | transmit 0) + Pr(receive 1 | transmit 1) - Pr(receive 0 | transmit 0) * Pr(receive 1 | transmit 1) = 0.996

since they're mutually exclusive? That seems wrong because it's > than the individual prob of 0.92 or 0.95. I also need to factor in the prob of each symbol being transmitted also.