3 cards are given from a pack of 52 playing cards. What is the probability that exactly one is a king?
(4 kings in a pack)
4/52 * 48/51 * 47/50 * 4
Is this correct?
3 cards are drawn from a pack of 52 playing cards.
What is the probability that exactly one is a King?
There are: 4 Kings and 48 Others.
Three cards are drawn: X. Y, Z.
The King can be in any of positions.
. . (King-Other-Other), (Other-King-Other), (Other-Other-King)
Suppose it is: (King-Other-Other)
. . The probability is: .
Why is it that the binomial coefficient calculation works?
Is it like:
(Number of ways of choosing 1 king out of 4)*(Number of ways of choosing 2 others out of 58)/(Number of ways of choosing 3 cards out of 52)
Is this conditional probability?