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Thread: Independant and Disjoint Events

  1. October 16th 2009, 05:23 PM #1
    Sakurazaki
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    Independant and Disjoint Events

    I have managed to figure out the first part, however the second part stumps me. Could someone walk me through this?

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  2. October 16th 2009, 09:51 PM #2
    mr fantastic
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    Quote Originally Posted by Sakurazaki View Post
    I have managed to figure out the first part, however the second part stumps me. Could someone walk me through this?

    You know that \Pr(E \cup F) = \Pr(E) + \Pr(F) - \Pr(E \cap F) .... (1)

    And if E and F are independent you know that \Pr(E \cap F) = \Pr(E) \cdot \Pr(F) .... (2)

    Substitute (2) into (1), then substitute the given data and solve for Pr(F).
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