Keekerik is an imaginary land where the people have an interesting three-stage ritual for couples who want to get married. Wandalina and Gerik are in that situation so they go the the hope of Queen Katalana to perform this ritual. Permission for them to marry as soon as they wish depends on the outcome of the ritual.

The queen greets them and reaches into a box and pulls out six identical strings for the ritual. The queen hands the strings to Wandalina who holds them firmly in her fist. One end of each string is sticking out above and below her fists.

The queen steps to the side and Gerik is called forward. He ties two of the ends together above Wandalina's fist. Then he ties two other ends above her fist together. Finally, he ties the last two ends above her fist together. The six ends below Wandalina's fist are still hanging untied.

Now Queen katalana comes forward again. Although she was watching Gerik, she has no idea which string end below Wandalina's fist belongs to which end above. The queen does the final step and randomly picks two of the ends below and ties them together, then two more, and finally the last two. So Wandalina now has six strings in her first with three knots above and three knots below.

Whether Wandalina and Gerik will be allowed to marry right away depends on what happens when Wandalina opens her first. If the six strings form one large loop, then they will. Otherwise, they will be required to wait and reapat the ritual in six months.

Questions:

A.When Wandalina opens her first and looks at the strings, what combination of different size loops might there be?

B. What is the probability that the strings will form one big loop? In other words, what are the chances that Wandalina and Gerik will be able to marry right away?

C. What is the probability for each of the other possible combinations?

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I'm no math expert (that's why I'm asking you), but I guess this entire problem is mostly about probability. How should I go about answering these questions? I'm totally stuck.