Hi, I'm completely new to this forum and, in fact, my maths is horrendous to say the least. I do have quite an advanced probability question I would like to work out though, for the purposes of a gambling experiment.

If someone can help, I would be very very grateful.

I need to know the probability (%) of winning a game where there are 100 numbers. 100,000 people pick six numbers. However, you can pick the same number twice or even three times and there is also a much higher chance that 10 of the 100 numbers will come up.

25 numbers are then selected at random. What is your chance of winning the game?

So to recap, 100,000 people pick 6 numbers each. 25 numbers are picked at random from 100, where each number can be selected twice or even three times, and some of the numbers (say 10 of them) have more weight attached to them so they have more of a chance of being selected.

If that makes sense to anyone and you might be looking for a good maths equation on a monday, I would be very grateful for your help.

Cheers,

Ronan