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Math Help - evalute answer will be a natural number

  1. #1
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    evalute answer will be a natural number

    2(15-11)^2/(3(2^2 - 2)^2 - 10^2) + (5-2^2)^2+3^2/(6-4)^2+3

    I worked it out like this

    2(15-11)^2/(3(2^2 - 2)^2 - 10^2) + (5-2^2)^2+3^2/(6-4)^2+3
    32/(12-10)^2+(1)^2+9/7
    32/4 + 10/7
    448+80/56= 9.4
    is this correct?
    Last edited by wolfhound; October 4th 2009 at 10:08 AM. Reason: mistake
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  2. #2
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    Quote Originally Posted by wolfhound View Post
    2(15-11)^2/(3(2^2 - 2)^2 - 10^2) + (5-2^2)^2+3^2/(6-4)^2+3

    I worked it out like this

    2(15-11)^2/(3(2^2 - 2)^2 - 10^2) + (5-2^2)^2+3^2/(6-4)^2+3
    32/(12-10)^2+(1)^2+9/7
    32/4 + 10/7
    448+80/56= 9.4
    is this correct?
    2(15-11)^2/(3(2^2 -2)^2 -10^2) + (5-2^2)^2 + 3^2/(6-4)^2 + 3

    2(15-11)^2/(3(2^2-2)^2-10^2) + (5-2^2)^2+3^2/(6-4)^2+3

    \dfrac{2(4^2)}{(3(2^2) - 10^2} + (5-4)^2 + \dfrac{3^2}{(6-4)^2} + 3

    \dfrac{32}{12 - 100} + 1 + \dfrac{9}{4} + 3


    \dfrac{32}{-88} + \dfrac{25}{4}

    \dfrac{-16}{44} + \dfrac{275}{44}


    \dfrac{259}{44}
    evalute answer will be a natural number
    It's a rational number.
    Is the original entry correct?

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  3. #3
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    Thanks for your reply aidan,I'm sorry I made a mistake on the division in the first part the^2 is not beside 10 its outside the )^2 after the 10

    2(15-11)^2/(3(2^2 - 2)^2 - 10)^2 + (5-2^2)^2+3^2/(6-4)^2+3

    Quote Originally Posted by aidan View Post
    2(15-11)^2/(3(2^2 -2)^2 -10^2) + (5-2^2)^2 + 3^2/(6-4)^2 + 3

    2(15-11)^2/(3(2^2-2)^2-10^2) + (5-2^2)^2+3^2/(6-4)^2+3

    \dfrac{2(4^2)}{(3(2^2) - 10^2} + (5-4)^2 + \dfrac{3^2}{(6-4)^2} + 3

    \dfrac{32}{12 - 100} + 1 + \dfrac{9}{4} + 3


    \dfrac{32}{-88} + \dfrac{25}{4}

    \dfrac{-16}{44} + \dfrac{275}{44}


    \dfrac{259}{44}
    It's a rational number.
    Is the original entry correct?

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