# Math Help - brackets within brackets

1. ## brackets within brackets

hi how would I work out the following?
(3(2^2 -2)^2 -10)^2

which brackets do I calculate first please?

2. Originally Posted by wolfhound
hi how would I work out the following?
(3(2^2 -2)^2 -10)^2

which brackets do I calculate first please?

1. $2^2-2 = {\color{red}2}$
2. ${\color{red}2}^2 = {\color{blue}4}$
3. $3 \times {\color{blue}4} = {\color{green}12}$
4. ${\color{green}12} - 10 = 2$
5. $2^2 = 4$

3. Thanks

5. ## value of x

find value of x if x-2 =5x + 14

I havent learned how to do these yet I just want to find out how and then I will catch on
Thanks

6. Originally Posted by wolfhound
find value of x if x-2 =5x + 14

I havent learned how to do these yet I just want to find out how and then I will catch on
Thanks

HI

$x-2=5x+14$

$x-5x=14+2$

$
-4x=16
$

$
x=-4
$

HI

$x-2=5x+14$

$x-5x=14+2$

$
-4x=16
$

$
x=-4
$
cool thanks

8. ## another find x

find value of x if
2x-1/x+2 = 3

and
is 5 a solution of x^2 + 3x-9=(x-4)(x+21)??
If so please explain how I do it
Thanks!!!!!

9. actually is x =7 the first one...

10. Originally Posted by wolfhound
find value of x if
2x-1/x+2 = 3

and
is 5 a solution of x^2 + 3x-9=(x-4)(x+21)??
If so please explain how I do it
Thanks!!!!!
HI again .

If you need any more help , its better to start a new thread . Well , i am going to answer this . If you have any more q's , start a new onw

$\frac{2x-1}{x+2}=3$

$2x-1=3(x+2)$

$2x-1=3x+6$

$x=-7$

$
x^2+3x-9=(x-4)(x+21)
$

$x^2+3x-9=x^2+17x-84$

$3x-9=17x-84$

$14x=75$

$x=75/14$

So 5 is not a solution .

HI again .

If you need any more help , its better to start a new thread . Well , i am going to answer this . If you have any more q's , start a new onw

$\frac{2x-1}{x+2}=3$

$2x-1=3(x+2)$

$2x-1=3x+6$

$x=-7$

$
x^2+3x-9=(x-4)(x+21)
$

$x^2+3x-9=x^2+17x-84$

$3x-9=17x-84$

$14x=75$

$x=75/14$

So 5 is not a solution .
Thanks so much for your help I will start a new thread when I have more questions...

12. You seem to have the wrong sign for both of them

$\frac{2(7)-1}{7+2} = \frac{13}{9} \neq 3$

by inspection $x = -7$

-----------------

For the 2nd one $31 \neq 26$ so 5 is not a solution

$x^2+3x-9 = x^2+17x-84$

$-14x = - 75$