hi how would I work out the following? (3(2^2 -2)^2 -10)^2 which brackets do I calculate first please?
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Originally Posted by wolfhound hi how would I work out the following? (3(2^2 -2)^2 -10)^2 which brackets do I calculate first please? Start with the innermost and move outwards:
Thanks
You can also use google calculator to check your answer. Paste the problem into google and hit search http://www.google.com/#hl=en&source=hp&q=%283%282^2+-2%29^2+-10%29^2&aq=f&aqi=&oq=&fp=e705e53e3f505592
find value of x if x-2 =5x + 14 more helps please I havent learned how to do these yet I just want to find out how and then I will catch on Thanks
Originally Posted by wolfhound find value of x if x-2 =5x + 14 more helps please I havent learned how to do these yet I just want to find out how and then I will catch on Thanks HI
Originally Posted by mathaddict HI cool thanks
How about this one find value of x if 2x-1/x+2 = 3 and is 5 a solution of x^2 + 3x-9=(x-4)(x+21)?? If so please explain how I do it Thanks!!!!!
actually is x =7 the first one...
Originally Posted by wolfhound How about this one find value of x if 2x-1/x+2 = 3 and is 5 a solution of x^2 + 3x-9=(x-4)(x+21)?? If so please explain how I do it Thanks!!!!! HI again . If you need any more help , its better to start a new thread . Well , i am going to answer this . If you have any more q's , start a new onw So 5 is not a solution .
Originally Posted by mathaddict HI again . If you need any more help , its better to start a new thread . Well , i am going to answer this . If you have any more q's , start a new onw So 5 is not a solution . Thanks so much for your help I will start a new thread when I have more questions...
You seem to have the wrong sign for both of them by inspection ----------------- For the 2nd one so 5 is not a solution
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