hi how would I work out the following?

(3(2^2 -2)^2 -10)^2

which brackets do I calculate first please?

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- Oct 4th 2009, 05:51 AMwolfhoundbrackets within brackets
hi how would I work out the following?

(3(2^2 -2)^2 -10)^2

which brackets do I calculate first please? - Oct 4th 2009, 06:15 AMe^(i*pi)
- Oct 4th 2009, 06:48 AMwolfhound
Thanks (Clapping)

- Oct 4th 2009, 07:03 AMe^(i*pi)
You can also use google calculator to check your answer. Paste the problem into google and hit search

http://www.google.com/#hl=en&source=hp&q=%283%282^2+-2%29^2+-10%29^2&aq=f&aqi=&oq=&fp=e705e53e3f505592 - Oct 4th 2009, 07:24 AMwolfhoundvalue of x
find value of x if x-2 =5x + 14

more helps please :)

I havent learned how to do these yet I just want to find out how and then I will catch on

Thanks - Oct 4th 2009, 07:25 AMmathaddict
- Oct 4th 2009, 07:45 AMwolfhound
- Oct 4th 2009, 07:51 AMwolfhoundanother find x
How about this one

find value of x if

2x-1/x+2 = 3

and

is 5 a solution of x^2 + 3x-9=(x-4)(x+21)??

If so please explain how I do it

Thanks!!!!! - Oct 4th 2009, 07:53 AMwolfhound
actually is x =7 the first one...

- Oct 4th 2009, 08:10 AMmathaddict
HI again .

If you need any more help , its better to start a new thread . Well , i am going to answer this . If you have any more q's , start a new onw

$\displaystyle \frac{2x-1}{x+2}=3$

$\displaystyle 2x-1=3(x+2)$

$\displaystyle 2x-1=3x+6$

$\displaystyle x=-7$

$\displaystyle

x^2+3x-9=(x-4)(x+21)

$

$\displaystyle x^2+3x-9=x^2+17x-84$

$\displaystyle 3x-9=17x-84$

$\displaystyle 14x=75$

$\displaystyle x=75/14$

So 5 is not a solution . - Oct 4th 2009, 08:14 AMwolfhound
- Oct 4th 2009, 08:18 AMe^(i*pi)
You seem to have the wrong sign for both of them

$\displaystyle \frac{2(7)-1}{7+2} = \frac{13}{9} \neq 3$

by inspection $\displaystyle x = -7$

-----------------

For the 2nd one $\displaystyle 31 \neq 26$ so 5 is not a solution

$\displaystyle x^2+3x-9 = x^2+17x-84$

$\displaystyle -14x = - 75$