Our alphabet contains 26 letters. Five of these letters are vowels (A, E, I, O, U). The remaining 21 letters are called consonants. Each letter of the alphabet is written on a card and you are asked to choose a card. What is the probability of choosing a consonant?
If you are looking for a how rather than an answer, I would recommend putting all related questions in one post. Such as doing a thread that would go like this:
Originally Posted by SymmetryOriginally Posted by AnswererOriginally Posted by SymmetryOriginally Posted by Answererand so on and so forth...Originally Posted by Symmetry
P.S. What level math are you in? Are you just learning these or have you gone through high-school and looking back on what you learned...
Quick,
Here is your answer. I am preparing for an upcoming June math state exam to get certified for grades 9-12. I have not been a high school student since 1984. I can do the basic stuff but there are questions where I get stuck. The questions I post here, after having done more than 25 correct on my own per end of chapter, are the complicated ones I was not able to solve. Is this clear?
Thanks for asking.
With equally likely outcomes the probability of an outcome from a favourable
set of outcomes is the ratio of the number of elements in the set of favourable
outcomes to the total number of possible outcomes.
Here we choose a card, the favoured set of outcomes is that that card
shows a consonant, there are 21 such elements among the equally likely
outcomes, and a total of 26 possible, equally likely outcomes. Hence the
desired probability is:
p=21/26.
This must be about the second thing you learn in probability.
The procedure is the same in all problems of this type:
1. Identify what the equaly likely outcomes are
2. Identify which of those are the favourable outcomes.
3. Count the favourable outcomes.
4. Count the equaly likely outcomes
5. The probability is the ratio of answer to 3 to the answer to 4.
RonL