I will do
One jar contains 6 blue marbles, 5 red marbles, 8 white marbles, and 8 goldenrod marbles. A second jar contains 8 blue marbles, 7 red marbles, 8 white marbles, and 6 goldenrod marbles. A marble is picked at random from the first jar and put into the second jar. A marble is then selected at random from the second jar. Find the probability that the marble selected from the second jar is a goldenrod. Give answer as a fraction reduced to lowest terms.
I think this problem is easier than I think but I keep getting messed up. Help please!
Hello, sweeetcaroline!
I'll simplify the wording . . .
There are two cases to consider . . .One jar contains 8 Gold marbles and 19 Others.
A second jar contains 6 Gold marbles and 23 Others.
A marble is picked at random from the first jar and put into the second jar.
A marble is then selected at random from the second jar.
Find the probability that the marble selected from the second jar is Gold.
[1] The first marble drawn is Gold: .
. . .Then the second jar contains: 7 Gold and 23 Others: .
. . .
[2] The first marble drawn is an Other: .
. . .Then the second jar contains: 6 Gold and 24 Others: .
. . .
Therefore: .