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Math Help - Canons

  1. #1
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    Canons

    Say, If 3 Canons, A, B, C, Have The Probability Of Hitting Their Targets, 0.5, 0.33, 0.25 Respectivly How Would I Calculate The Probability Of:

    a. None Of Them Hitting.
    b. Exactly One Of Them Hitting.
    c. Exactly Two of Them Hitting.

    I Have Tried Different Approaches, Each Giving Me Strange Results, So Please Help
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  2. #2
    kin
    kin is offline
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    Quote Originally Posted by olekaiwalker View Post
    Say, If 3 Canons, A, B, C, Have The Probability Of Hitting Their Targets, 0.5, 0.33, 0.25 Respectivly How Would I Calculate The Probability Of:

    a. None Of Them Hitting.
    b. Exactly One Of Them Hitting.
    c. Exactly Two of Them Hitting.

    I Have Tried Different Approaches, Each Giving Me Strange Results, So Please Help
    a) the probability of none of them hitting
    = the complement of at least one of them hitting
    =P( ( A or B or C)' )
    =1-P( A or B or C)
    =1- [P(A)+P(B)+P(C)-P(AB)-P(AC)-P(BC)+P(ABC)]

    b) the required P = P(AB'C' or A'BC' or A'B'C)
    the above 3 cases are mutually exclusive..
    so the ans = adding the probability of each case

    c) similar approach as (b)
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