Hi All,

I think I have the right answer for this, but I'm not that confident on these questions..

Three radar sets, operating independently, are set to tdetect any aircraft flying through a certain area. Each set has a probability of .02 of failing to detect a plane in its area. If an aircraft enters the area, what is the probability that it

agoes undeteected?

bis detected by all three radar sets?

So I defined the events;

$\displaystyle B_{1}$ - first fails

$\displaystyle B_{2}$ - second fails

$\displaystyle B_{3}$ - third fails.

Then $\displaystyle P(a)=P(B_{1} \cup B_{2} \cup B_{3})$$\displaystyle =P(B_{1})+P(B_{2})+P(B_{3}) $$\displaystyle - \left[ P(B_{1} \cap B_{2} )+P(B_{1} \cap B_{3} )+P(B_{2} \cap B_{3} )\right] + \left[ P(B_{1} \cap B_{2} \cap B_{3})\right]$

With $\displaystyle P(B_{1} \cap B_{2})=P(B_{2} \cap B_{3} )=P(B_{2} \cap B_{3} )=0.02 \cdot 0.02 = 0.0004$

and $\displaystyle P(B_{1} \cap B_{2} \cap B_{3})=0.02 \cdot 0.02 \cdot 0.02 = 0.000008$

So $\displaystyle P(a) = 0.02+0.02+0.02-\left[ 0.0004+0.0004+0.0004\right] + 0.000008=0.058808$

Andbdetected by all three;

$\displaystyle P(b)=P(\bar{B_{1}} \cap \bar{B_{2}} \cap \bar{B_{3}}=0.98 \cdot 0.98 \cdot 0.98=0.941192$

Thanks for any help