the first bag contains totally 5 coins,
if u take the a gold coin from it ,
p(C|A)=3/5
Given two bags, where the first bag contains 3 gold coins and two silver coins and the second bag contains 4 gold coins and 6 coins, determine the probability that a coin chosen randomly between the two bags in gold.
Let A be the event of choosing from the first bag
B be the event of choosing from the second bag
C be the event of choosing a gold coin.
The probability of choosing a gold coin between the 2 bags is
Why does , isn't it ? Or did they just write the answer reversed (which they shouldn't do)?