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If a person with weapon walks thru the security check point, the probability of the check point correctly alarmed is .92. If a person without weapon walks thru, the check point falsely alarmed its danger with the probability of .08. Suppose that the probability of a person with weapons show up is 0.05.
Find the probability that a person has weapon if the checkpoint was not alarmed.
My solution so far:
I let, and
So I'm looking for
But how do I find? Thank you.
or by the Baye's Theorem, I know that = \frac {P(A^c)}{ P(W) }P(A^c \mid W) )
