Thread: A question from my quiz today

Suppose two boys named Davis, three boys named Jones, and four boys named Smith are arranged at random in a row containing nine seats.
-How many arrangements can be made so that boys wearing the same name will stay together?

I think it's 3 nPr 3.

Originally Posted by Chizum

Suppose two boys named Davis, three boys named Jones, and four boys named Smith are arranged at random in a row containing nine seats.
-How many arrangements can be made so that boys wearing the same name will stay together?