...which simplifies to !2) A balanced coin is tossed four times. The coin tosses are independent, so the two outcomes per toss (H,T) are equally likely for each coin toss.
i) Calculate the probability that exactly two of the four tosses results in tails...
--------I think its just 6/16...not sure though!
Since we're dealing with a binomial distribution: , .ii) Calculate the probability that more than one toss results in heads..
It would be3) A manufacturer has five seemingly identical computer monitors available for shipping. Unknown to him, two are defective. An order is place for one monitor. What is the probability that the defective monitor is shipped?
------------------I think its just... 5c1 / 5c2 = 1/2??
thanks for the help in advance!
Does this make sense?