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Math Help - natural log

  1. #1
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    natural log

    e^x+e^{-x}=3

    How do you solve for x here?
    Last edited by DarthBlood; August 31st 2009 at 11:32 AM. Reason: correctly edited -x exponent
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  2. #2
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    Quote Originally Posted by DarthBlood View Post
    e^x+e^-x=3

    (note: that's e to the negative x power, i just don't know how to show that, sorry.)

    How do you solve for x here?
    BTW: If you have more than one character in an exponent, set off the whole exponent in braces.
    [tex]e^{-x}[/tex] gives  e^{-x} instead of  e^-x .
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  3. #3
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    Quote Originally Posted by DarthBlood View Post
    e^x+e^{-x}=3
    How do you solve for x here?
    e^x+e^{-x}=3 multiply by e^x.
    e^{2x}-3e^x+1=.

    Can you solve w^2-3w+1=0?
    If so let z=e^x.
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  4. #4
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    Quote Originally Posted by Plato View Post

    Can you solve w^2-3w+1=0?
    errr....no sorry.
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  5. #5
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    For ax^2+bx+c=0

     x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}
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  6. #6
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    Quote Originally Posted by Plato View Post
    e^x+e^{-x}=3 multiply by e^x.
    e^{2x}-3e^x+1=.
    Can you solve w^2-3w+1=0?
    If so let z=e^x.
    Quote Originally Posted by DarthBlood View Post
    errr....no sorry.
    May I, with all due respect, ask this question?
    If you cannot do a basic beginning algebra question, then why are you being asked to do an advanced algebra question involving exponentials?
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  7. #7
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    There's my problem: I keep forgetting to add "with all due respect"!
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  8. #8
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    lol i've forgotten everything over the summer break...i honestly forgot that i could use that equation to solve it.
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