# A logarithm

• Aug 30th 2009, 12:39 PM
Minieke
A logarithm
http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif

how exactly do i do this? i keep getting stumped
im sorry.
i put the image up on photobucket
• Aug 30th 2009, 01:00 PM
e^(i*pi)
Quote:

Originally Posted by Minieke
http://www.redcomet.net/ctc/Ma25b-EP2.gif

how exactly do i do this? i keep getting stumped

• Aug 30th 2009, 03:11 PM
Minieke
http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif
New image for people who couldn't see it.
• Aug 30th 2009, 03:35 PM
skeeter
Quote:

Originally Posted by Minieke
http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif
New image for people who couldn't see it.

what does this numerical quotient have to do with logarithms?
• Aug 30th 2009, 03:59 PM
Minieke
the problem has to be evaluated by using logs
• Aug 30th 2009, 04:01 PM
pacman
maybe the x in italics are multiplication symbols and logarithm will be used to simplify the expression
• Aug 30th 2009, 04:17 PM
eXist
Can you further explain the problem please? Directions, other info, etc.
• Aug 30th 2009, 07:54 PM
Minieke
Quote:

Originally Posted by eXist
Can you further explain the problem please? Directions, other info, etc.

i did, the only directions are to solve by using logs
• Sep 1st 2009, 07:13 AM
pacman
then let y = http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif,

Then,

log y = (1/3)log(24-34) + log(201.7) - (1/3)log(3.67)-(1/2)log (16.72)

y = antilog[(1/3)log(24-34)+log(201.7)-(1/3)log(3.67)-(1/2)log(16.72)];

BUT, (Crying) this alone should bother you: (1/3)log(24-34)