http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif

how exactly do i do this? i keep getting stumped

im sorry.

i put the image up on photobucket

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- August 30th 2009, 12:39 PMMiniekeA logarithm
http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif

how exactly do i do this? i keep getting stumped

im sorry.

i put the image up on photobucket - August 30th 2009, 01:00 PMe^(i*pi)
- August 30th 2009, 03:11 PMMinieke
http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif

New image for people who couldn't see it. - August 30th 2009, 03:35 PMskeeter
- August 30th 2009, 03:59 PMMinieke
the problem has to be evaluated by using logs

- August 30th 2009, 04:01 PMpacman
maybe the

in italics are multiplication symbols and logarithm will be used to simplify the expression**x** - August 30th 2009, 04:17 PMeXist
Can you further explain the problem please? Directions, other info, etc.

- August 30th 2009, 07:54 PMMinieke
- September 1st 2009, 07:13 AMpacman
then let y = http://i849.photobucket.com/albums/a.../Ma25b-EP2.gif,

Then,

log y = (1/3)log(24-34) + log(201.7) - (1/3)log(3.67)-(1/2)log (16.72)

y = antilog[(1/3)log(24-34)+log(201.7)-(1/3)log(3.67)-(1/2)log(16.72)];

BUT, (Crying) this alone should bother you: (1/3)log(24-34)