I'm stuck on this problem...what did i do wrong?
d(t)=(velocity) (t)+1/2 (acceleration) (t)^2
cycles 4 meters per second
rate of .4 meters per second squared
vertical distance from top to bottom of hill is 25 meters
How long until goes down the hill?
From the quad formula I got 1/4 and -5/2, but the answer is 5 seconds....why?