Originally Posted by
clips 
can someone help me with this,its very quick
(3y^3 - 9y^2 - 3)
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Originally Posted by
clips can someone help me with this,its very quick
(3y^3 - 9y^2 - 3)
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Originally Posted by
clips divided by
)
and if anyone can quickly explain the remainder theorem that would be appreciated. thanks a lot!
goes into
times so you have:
 = 3y^3 + y)
Subtract the result from the dividend:
 = -9y^2 - y - 3)
Now repeat the process:
, the largest degree term of your divisor, goes into -
... -3 times so you have:
 = -9y^2 - 3)
Subtract the result from
:
 = -y)
3y^2 is of greater degree than -y so -y is the remainder.
The quotient is y-3 and the remainder is -y
Check using:
Dividend = quotient * divisor + remainder
Remainder theorem:
If you divide a polynomial p(x) by a factor (x-a), the remainder is p(a). In plain English: the remainder is the y-value you get if you evaluate the polynomial at x=a.
example:
If you divide
 = x^200 + 3x^99 + 2x - 1 )
by
)
, the remainder is
)
, which is
. Note that we can conclude about the remainder without knowing the quotient.
I hope this helps.
Good luck!
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