First of all, be careful of the order of things.
We want . Note the order.
ABCD is a parallelogram with vertices A=(-1,2,-1), B=(2,-1,3), and D=(-3,1-3), find the coordinates of C.
So this is my work below, BUT i cannot seem to get the correct coordinates of C, as my diagram does not seem to look exactly like a parallelogram..
I sketched A, B, D..
A is on the y-axis , D is below it to the right and in 4th quadrant, B is in second quadrant.. so I assumed that C would be in 2nd qadrant.
The vector AC= The vector DB
since they are parallel
(x+1,y-2,z+1)=(5,-2,6)
x+1=5
x=4
y-2=-2
y=0
z+1=6
z=5
C(4,0,5)
Plato is correct. The vector AC is not parallel with the vector DB. Look at this picture (this is as if it were flattened into ):
What I would do is find the equation of the line BC and the line DC, and then find their intersection. That intersection should be C.
well actually I am having trouble plotting the points like A(-1,2,-1) B(2,-1,3) and D(-3,1,-3) in 3 space, my teacher said to plot the vertex of the point first, and then you should have 3 lines forming a corner of a cube.. and then draw your cube, so that the arrow goes from orgin to opposite side of cube. is there a better method of doing this? because I seem to mess up the points where I am plotting A, B, and D, so then my parallelogram vertices are in the wrong quadrant .. thus wrong order