First of all, be careful of the order of things.
We want . Note the order.
ABCD is a parallelogram with vertices A=(-1,2,-1), B=(2,-1,3), and D=(-3,1-3), find the coordinates of C.
So this is my work below, BUT i cannot seem to get the correct coordinates of C, as my diagram does not seem to look exactly like a parallelogram..
I sketched A, B, D..
A is on the y-axis , D is below it to the right and in 4th quadrant, B is in second quadrant.. so I assumed that C would be in 2nd qadrant.
The vector AC= The vector DB
since they are parallel
Plato is correct. The vector AC is not parallel with the vector DB. Look at this picture (this is as if it were flattened into ):
What I would do is find the equation of the line BC and the line DC, and then find their intersection. That intersection should be C.
well actually I am having trouble plotting the points like A(-1,2,-1) B(2,-1,3) and D(-3,1,-3) in 3 space, my teacher said to plot the vertex of the point first, and then you should have 3 lines forming a corner of a cube.. and then draw your cube, so that the arrow goes from orgin to opposite side of cube. is there a better method of doing this? because I seem to mess up the points where I am plotting A, B, and D, so then my parallelogram vertices are in the wrong quadrant .. thus wrong order