Write an equation for the given line:

1. P(2,3), m=2

2. P(1,0), no slope

3. P (-1,2), m=-1/2

4. P(2,3), m = 0

1.y=2(x-2)+3

2. y=(x-1)

3. y= -1/2(x+1)+2

4. y=(x-2)+3

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- Aug 27th 2009, 06:22 AMyitsonggAre my answers correct to these problems?
Write an equation for the given line:

1. P(2,3), m=2

2. P(1,0), no slope

3. P (-1,2), m=-1/2

4. P(2,3), m = 0

1.y=2(x-2)+3

2. y=(x-1)

3. y= -1/2(x+1)+2

4. y=(x-2)+3 - Aug 27th 2009, 06:49 AMHaytham
no slope or m=0, means the line is horizontal, having the same y-value for all x

so it doesnt depends of x

2 and 4 arent correct - Aug 27th 2009, 07:13 AMVonNemo19
The point-slope form of the equation to a line is given by $\displaystyle (y_2-y_1)=m(x_2-x_1)$.

The answer you have for the first problem is correct. In the second problem, however, your are asked to find the equation to a line that goes through the point $\displaystyle (1,0)$ that hasimplies that the line is vertical. Thus, the equation is $\displaystyle x=1$.*no slope. No slope*

Number 3 is correct.

Number 4 is wrong. If I use the formula that I have written at the beginning og this post, I have

$\displaystyle y-3=0(x-2)$

$\displaystyle y-3=0$

$\displaystyle y=3$

This is a horizontal line, as is expected given a slope of 0. - Aug 27th 2009, 07:18 AMyitsongg
Thanks